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Home/ Questions/Q 7169999
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T15:07:24+00:00 2026-05-28T15:07:24+00:00

See i have this following code below, at line no.9 i’m calculating some dates

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See i have this following code below, at line no.9 i’m calculating some dates to move forward, so im using AddDays method but in return i’m getting all dates same for all rows.

If i do AddDays(6) like this then it is returning correctly by moving all dates by 6 days.

How should i do it for adding days according to my logic at this point.

[DataContract]
public class JQGridRow
    {
        [DataMember]
        public long id;
        [DataMember]
        public object[] cell;
    }
   var sortedItems = invBatch.ListOfItems.OrderBy(i => i.RunDateIndex);//This will return IEnumerable<Class> List

DateTime startDate = DateTime.Parse(lblStartDate.Text);
JQGrid.JQGridRow[] rowData = (
        from i in sortedItems
        select new JQGrid.JQGridRow() {
        id = i.ID,
        cell = new string[] { 
        i.ID.ToString(),
        i.Status.ToString(),
        i.StatusTitle,
        i.RunDate.AddDays((startDate.Subtract(i.RunDate)).Days+1).ToString(Utility.DATE_FORMAT),
        //Here in above line the array returning same values for all columns of this row        
        i.StartTimeString,  
        i.EndTimeString, 
        i.EndTime.ToString(), 
        }}).ToArray();
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  1. Editorial Team
    Editorial Team
    2026-05-28T15:07:25+00:00Added an answer on May 28, 2026 at 3:07 pm

    The dates are all same and equal the next day after startDate because you calculate them as such.

    i.RunDate.AddDays((startDate.Subtract(i.RunDate)).Days+1)
    

    Rounding to whole day, you compute RunDate+(startDate-RunDate+1) = startDate + 1. i.RunDate does not matter.

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