Question

See this example!

int main( int argc, char ** argv )
{
    int *ptr = malloc(100 * sizeof (int));

    printf("sizeof(array) is %d bytes\n", sizeof(ptr));
}

The printf function return only 4 bytes!
What is wrong?

Thanks so much!!!

Answer 1

Nothing is wrong. You are asking for, and getting, the size of the pointer on your platform.

It is not in general possible to get the size of the memory block that a pointer points at, you must remember it yourself if you need it later.