Question

see what I have:

> bar = [(u'code__regex', u'^[^J]'), (u'active__exact', u'0'), (u'type__id__exact', u'E01')]

There are the fields/values that I want to use to filter the model Foo.

> #want to have this equivalent:
> Foo.objects.filter(bar)

Thanks!

Answer 1

Foo.objects.filter(**dict(bar))

This isn’t a django issue, this is a python issue. You want to pass the keyword pairs as keyword arguments (kwargs) to the filter. Your bar is perfect as a kwarg set, so the dict(bar) converts it to the dictionary, and the ** prefix informs the python parser that the dictionary is to be interpreted as keyword arguments by the receiver.

Stack overflow entry Understanding kwargs in Python covers this in more detail.