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Home/ Questions/Q 743533
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T08:52:30+00:00 2026-05-14T08:52:30+00:00

SELECT AVG(`col5`) FROM `table1` WHERE `id` NOT IN ( SELECT `id` FROM `table2` WHERE

  • 0
    SELECT AVG(`col5`)
    FROM `table1`
    WHERE `id` NOT IN (
        SELECT `id` FROM `table2`
        WHERE `col4` = 5
    )
    group by `col2` having sum(`col3`) > 0
UNION
    SELECT MAX(`col5`)
    FROM `table1`
    WHERE `id` NOT IN (
        SELECT `id` FROM `table2`
        WHERE `col4` = 5
    )
    group by `col2` having sum(`col3`) = 0

For readability and performance reasons, I think this code could be refactored. But how?

EDITIONS

  1. removed the outer select

  2. made the first select to return a sum and the second one to return another value

  3. replaced the SUM by AVG

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T08:52:30+00:00Added an answer on May 14, 2026 at 8:52 am
    SELECT * 
    FROM table1 t1
    left outer join table2 t2 on t1.id = t2.id and t2.col4 = 5
    where t2.id is null
    group by t1.col2 
    having sum(col3) >= 0 
    

    The outer select is missing the FROM clause and was not adding anything so I removed it. The NOT IN is inefficient compared to the LEFT OUTER JOIN method so I replaced that. The two UNIONs were easily combined into one by using >=.

    Update:
    Note the use of UNION ALL rather than UNION. I don’t think you want to remove duplicates, and it will perform faster this way.

    SELECT AVG(t1.col5) 
    FROM table1 t1 
    left outer join table2 t2 on t1.id = t2.id and t2.col4 = 5 
    where t2.id is null 
    group by t1.col2  
    having sum(t1.col3) > 0  
    UNION ALL
    SELECT MAX(t1.col5) 
    FROM table1 t1 
    left outer join table2 t2 on t1.id = t2.id and t2.col4 = 5 
    where t2.id is null 
    group by t1.col2  
    having sum(t1.col3) = 0  
    
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