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Home/ Questions/Q 3287218
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T20:28:06+00:00 2026-05-17T20:28:06+00:00

SELECT COUNT( sendbook.id ) AS total, SUM( sendbook.num ) AS num, ( SELECT COUNT(

  • 0
SELECT COUNT( sendbook.id ) AS total, SUM( sendbook.num ) AS num, (

SELECT COUNT( sendbook.id )
FROM sendbook
INNER JOIN clients ON clients.id = sendbook.clientid
WHERE sendbook.issueid = '29'
AND clients.area >1000
AND clients.area <2000
) AS area1000, (

SELECT COUNT( sendbook.id )
FROM sendbook
INNER JOIN clients ON clients.id = sendbook.clientid
WHERE sendbook.issueid = '29'
AND clients.area >2000
AND clients.area <3000
) AS area2000, (

SELECT COUNT( sendbook.id )
FROM sendbook
INNER JOIN clients ON clients.id = sendbook.clientid
WHERE sendbook.issueid = '29'
AND clients.area >3000
AND clients.area <4001
) AS area2000
FROM `sendbook`
WHERE sendbook.issueid = '29' 

total  num  area1000  area2000  area2000
 8      438      3         3        2

Do you know a way to simplify this query?
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T20:28:06+00:00Added an answer on May 17, 2026 at 8:28 pm

    you need to use case statement something like this :

    SELECT  COUNT( sendbook.id ),
    (CASE 
    WHEN clients.area between '1000' and '2000'  THEN 1 
    WHEN clients.area between '2000' and '3000'  THEN 2 
    WHEN clients.area between '3000' and '4000'  THEN 3 
     END) AS myrange  FROM mytable 
    GROUP BY myrange
    
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