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Home/ Questions/Q 6055785
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T08:18:12+00:00 2026-05-23T08:18:12+00:00

SELECT count( t1.id ) , t2.special_value FROM table_1 AS t1, table_2 AS t2 WHERE

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SELECT count( t1.id ) , t2.special_value
FROM table_1 AS t1, table_2 AS t2
WHERE t1.`group` = 'val'
AND t2.code = 'val'

returns

count - normal value
special_value - NULL

but

SELECT t2.special_value
FROM table_2 AS t2
WHERE t2.code = 'val'

returns

special_value - another normal value

why first query works wrong?..

currently, i need

(count( t1.id ) + t2.special_value)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T08:18:13+00:00Added an answer on May 23, 2026 at 8:18 am

    This is why you should never use SQL’89 implicit join syntax.

    You have no join condition resulting in a cross join.

    Rewrite the query using explicit join syntax:

    SELECT count( t1.id ) , t2.special_value
    FROM table_1 AS t1
    INNER JOIN table_2 AS t2 ON (t1.`group` = t2.code)    <<-- join condition here
    WHERE ....                                            <<-- filter condition here
    GROUP BY ....                                         <<-- group by field here
    

    I don’t know how table t1 and t2 are linked, so you’ll have to tweak this a bit, but that’s how it supposed to work.
    And please never ever use implicit where joins again.

    Remarks
    I’m wondering what p.`group` and pp.code are, but I’m guessing you meant to write t1.`group` and t2.code

    You only need to escape fields and tablenames in ` backticks if they are reserved words.
    Personally all those backticks make me dizzy, but that’s just me.

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