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Asked: 2026-05-25T14:03:17+00:00

SELECT DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE())+1,0)) LastDay_CurrentMonth Hi everyone I have a query to find the last

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SELECT DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE())+1,0))
 LastDay_CurrentMonth

Hi everyone I have a query to find the last day of current month, which is surely working well, but I am unable to understand it, because I have other similar requirements and have to change it accordingly.

Can somebody explain it to me..
Thanks in advance

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1 Answer

  1. Editorial Team

    Get the DateTime of Now

    GETDATE() -- 2011-09-15 13:45:00.923

    Calculate the difference in month’s from ‘1900-01-01’

    DATEDIFF(m, 0, GETDATE()) -- 1340

    Add the difference to ‘1900-01-01’ plus one extra month

    DATEADD(m, DATEDIFF(m, 0, GETDATE())+1, 0) -- 2011-10-01 00:00:00.000

    Remove one second

    DATEADD(s, -1, DATEADD(m, DATEDIFF(m, 0, GETDATE())+1, 0)) -- 2011-09-30 23:59:59.000
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