Question

SELECT DISTINCT Database1.dbo.tblCustomers.SiteNum

FROM Database1.dbo.tblCustomers
LEFT OUTER JOIN tblWebUsers on tblWebUsers.SiteNum = Database1.dbo.tblCustomers.SiteNum

WHERE **tblWebUsers.ID = '4'**

This returns all sitenums relating to a webuser id but how do i do the opposite? i.e. return all site numbers not associated to a webuser id – I have tried not in (4) but it just returns all webusers site numbers that don’t have an id … I want it from database1

Answer 1

It’s still not clear what the opposite would be (we don’t have any sample data and expected results to work with, and only you can see your actual database), but I’d note that having tblWebUsers.ID = '4' in your where clause is forcing the left join to become an inner join.

This may be closer to what you want:

SELECT DISTINCT Database1.dbo.tblCustomers.SiteNum

FROM Database1.dbo.tblCustomers
LEFT OUTER JOIN tblWebUsers on
      tblWebUsers.SiteNum = Database1.dbo.tblCustomers.SiteNum and
      tblWebUsers.ID = '4'

Or more editable into the final form you’re seeking.

---

In fact, I think that this is what you’re wanting:

SELECT DISTINCT Database1.dbo.tblCustomers.SiteNum

FROM Database1.dbo.tblCustomers
LEFT OUTER JOIN tblWebUsers on
      tblWebUsers.SiteNum = Database1.dbo.tblCustomers.SiteNum and
      tblWebUsers.ID = '4'
WHERE
    tblWebUsers.ID is null

That is, you want to find rows from tblCustomers which do not have a row in tblWebUsers with ID equal to 4. But again, it would be better if you could more clearly explain what you’re trying to achieve, hopefully with sample data and expected results.