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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T17:27:32+00:00 2026-05-12T17:27:32+00:00

SELECT * FROM a JOIN (SELECT * FROM b WHERE b.aId = a.Id) AS

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SELECT * FROM a 
JOIN (SELECT * FROM b WHERE b.aId = a.Id) AS c ON c.aId = a.Id

It says does not recognize: a.Id in the Where Clause.

I know its probably cause im using a temp table and a.Id cannot be passed through but is there any way we can do that?

Because here is what actually happens

SELECT * 
  FROM a 
  JOIN (SELECT * FROM b 
         WHERE b.aId = a.Id 
      ORDER BY b.dateReg DESC
         LIMIT 1) AS c ON c.aId = a.Id

I need the ORDER BY b.dateReg DESC LIMIT 1 as it returns me the last row that assosiates with the a Table.. If you require i can post the Create Query

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T17:27:32+00:00Added an answer on May 12, 2026 at 5:27 pm

    — find last rows on b

    select * from b x 
    where exists(
         select id 
         from b y 
         where y.id = b.id 
         having max(y.dateReg) = x.dateReg
         group by id
         )
    

    — then join that b to a, this is the final query:

    select * from a
    join 
    (
         select * from b x 
         where exists(
             select id 
             from b y 
             where y.id = b.id 
             having max(y.dateReg) = x.dateReg
             group by id
             )
    
    ) as last_rows on last_rows.id = a.id
    

    — simpler:

    select * 
    from a join b x on a.id = x.id
    where exists(
        select id
        from b y
        where y.id = b.id
        having max(y.dateReg) = x.dateReg
        group by id)
    

    — or if you will use postgres:

    select DISTINCT ON (a.id) * 
    from a join b x on a.id = x.id
    order by a.id, b.dateReg DESC
    -- look ma! no group by!    
    
    -- nothing beats postgresql's simplicity :-)
    
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