Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7865127
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 2, 20262026-06-02T23:59:28+00:00 2026-06-02T23:59:28+00:00

SELECT * FROM {$dbp}auctions au, ic.imgurl LEFT JOIN {$dbp}cache ic ON au.cache_id = ic.id

  • 0
SELECT * 
FROM {$dbp}auctions au, ic.imgurl 
LEFT JOIN {$dbp}cache ic ON au.cache_id = ic.id

I’m baffled on where to set the alias for the second table (ic) and still only select the one column (imgurl).

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-02T23:59:30+00:00Added an answer on June 2, 2026 at 11:59 pm
    "SELECT au.*, ic.imgurl FROM {$dbp}auctions au  
    LEFT JOIN {$dbp}cache ic ON au.cache_id = ic.id" 
    

    I think this is close to what you want. Your original query is selecting everything.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

SELECT * FROM tbl_group_join tgj LEFT JOIN tbl_groups tg ON tg.group_id = tgj.group_id LEFT
SELECT * from `employees` a LEFT JOIN (SELECT phone1 p1, count(*) c, FROM `employees`
SELECT * FROM tableFoo LEFT JOIN tableBar ON tableFoo.commonColumn = tableBar.commonColumn WHERE tableBar.commonColumn IS
SELECT * FROM TAB1 LEFT JOIN TAB2 ON TAB2.ID_TAB1 = TAB1.ID JOIN TAB3 ON
SELECT * FROM Table_A LEFT JOIN Table_B ON (Table_A.A_ID = Table_B.A_ID) INNER JOIN Table_C
SELECT * FROM `resumes` AS r LEFT JOIN seeker_data_cached AS c ON r.user_id =
SELECT * FROM table1 LEFT JOIN table2 ON table1.id = table2.table1_id WHERE table1.id =
SELECT * FROM table1 JOIN table2 ON table1.center BETWEEN table2.left AND table2.right I'm new
Consider: SELECT * FROM `product` left join category on product.category_id = category.id This query
SELECT * FROM ExternalQuestionKeyword INNER JOIN ExternalKeywords ON ExternalKeywords.ID=ExternalQuestionKeyword.KeywordID WHERE QuestionID = 17

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.