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Editorial Team
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Asked: 2026-05-16T04:19:34+00:00

SELECT * FROM `objects` WHERE (user_id IN (‘7,8,12,9’) AND visibility IN (‘0,1’)); but it

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SELECT * FROM `objects` WHERE (user_id IN ('7,8,12,9') AND visibility IN ('0,1'));

but it only returns the stuff corresponds to the second array’s first element.
So it returns the same as like this: 

SELECT * FROM `objects` WHERE (user_id IN ('7,8,12,9') AND visibility IN ('0'));

(I swapped the two values (of the visibility arg) and completely different set of results was returned. What I want, is both of results in one Query.

It’s doing the same thing for the first array too. Only using the first value.

I would like the results from ALL the values.

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1 Answer

  1. Editorial Team

    You need to quote each value if its a string:

    SELECTobjectsWHERE (user_id IN ('7','8','12','9') AND visibility IN ('0','1'));

    Or of youre actually dealing with integers you could do:

    SELECTobjectsWHERE (user_id IN (7,8,12,9) AND visibility IN (0,1));

    Also where is your FROM clause?

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