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Home/ Questions/Q 6238117
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T11:09:12+00:00 2026-05-24T11:09:12+00:00

<select id=list multiple=multiple> <option value=1 id=one selected=selected>one </option> <option value=2 id=two selected=selected>two </option> <option

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<select id="list" multiple=multiple>
    <option value="1" id="one" selected="selected">one </option>
    <option value="2" id="two" selected="selected">two </option>
    <option value="3" id="three">three </option>
</select>

<ul id="uli">
    <li aaa="one">one</li>
    <li aaa="two">two</li>
    <li aaa="three">three</li>
</ul>

With the CSS:

.back {
 color: red;
}

And the Javascript:

$("#list").find("option:selected").each(function() {
    // logic here
});

Into the each() callback, I want to add class for equivalent in uli. I would like to use addClass(.back) for li where attr aaa == id for list.

live: http://jsfiddle.net/yjL9n/3/

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  1. Editorial Team
    Editorial Team
    2026-05-24T11:09:13+00:00Added an answer on May 24, 2026 at 11:09 am

    $(‘li[aaa=’ + this.id + ‘]’).addClass(‘back’);

    $('table').find('td[aaa="'+this.id+'"]').addClass('back');
    

    added to the inner part of your fiddle will do it. Updated based on comment from OP.

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