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Home/ Questions/Q 7703787
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T23:32:18+00:00 2026-05-31T23:32:18+00:00

<select id=select> <option value=1>1adsd</option> <option value=2>2adsd</option> <option value=3>3adsd</option> <option value=4>4adsd</option> <option value=5>5adsd</option> </select> var

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<select id="select">
    <option value="1">1adsd</option>
    <option value="2">2adsd</option>
    <option value="3">3adsd</option>
    <option value="4">4adsd</option>
    <option value="5">5adsd</option>
</select>

var parray = ['2', '5'];
    $("#select").live('change', function(){
        if($.inArray($(this).val(), parray)){
            console.log('yes');
            console.log($(this).val());
            console.log(parray);
        } else {
            console.log('no');
            console.log($(this).val());
            console.log(parray);
        }
    })

Why this doesnt working correctly?

if i select value 1 this show me ‘yes’ but “1” isnt in parray.

if i select value 2 this show me ‘no’ but “2” is in parray.

if i select value 5 this show me ‘yes’ – only this is OK. Why?

LIVE:

http://jsfiddle.net/G5D2V/

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  1. Editorial Team
    Editorial Team
    2026-05-31T23:32:19+00:00Added an answer on May 31, 2026 at 11:32 pm

    As the manual clearly states:

    $.inArray returns -1 if the element is not found, or the index where the element has been found (beginning at 0) otherwise.

    if($.inArray($(this).val(), parray) >= 0) {
    
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