Question

select left(emailaddress, len(emailaddress) - charindex('@', emailaddress))

I am getting the result below:

foo@ma

Please correct the select statement below. I need to do this with tones of email addresses and extract the username ONLY.

Answer 1

You’re inadvertently re-implementing “right” there 🙂

Try this:

select left(emailaddress, charindex('@', emailaddress) - 1)

It seeks the position of the @, and takes the number of characters up to but not including (that’s the - 1) the @ symbol.

Be careful with strings that don’t have an @ though; you’ll end up an empty string.