Question

SELECT "Name""Month","Year","Value" 
from Table
WHERE 
    "Name" LIKE '%JERRY%'
AND "Year" = 
    (SELECT MAX("Year") FROM Table where "Name" LIKE '%JERRY%')
AND "Month"= 
    (SELECT MAX("Month") FROM Table 
     where 
        "Name" LIKE '%JERRY%' 
    AND "Year"= (SELECT MAX("Year") FROM Table where "Name" LIKE '%JERRY%'))

Table –>

Name  | Year | Month | Value
-----------------------------
JERRY   2012    9        100           
JERRY   2012    9        120         
JERRY   2012    9        130           
JERRY   2012    8         20        
JERRY   2011    12        50           

So i want the first three rows as output. As for the latest month for the latest year i need all the values.
Can someone suggest a better cleaner query?

Answer 1

If there are other people in the table then you probably want to use a ranking function: Something like:

DECLARE @sample TABLE (
      [Name] VARCHAR(255)
    , [Year] INT
    , [Month] INT
    , [Value] INT
    )

INSERT @sample ([Name], [Year], [Month], [Value])
VALUES ('JERRY', 2012, 9, 100)           
     , ('JERRY', 2012, 9, 120)
     , ('JERRY', 2012, 9, 130)
     , ('JERRY', 2012, 8, 20)
     , ('JERRY', 2011, 12, 50)
     , ('FRED', 2011, 12, 50)
     , ('FRED', 2011, 12, 120)
     , ('FRED', 2011, 7, 150)

SELECT *
FROM (
    SELECT *
         , RANK() OVER (PARTITION BY [Name] ORDER BY [Year] DESC, [Month] DESC) AS [rnk]
    FROM @sample
    )
    AS samp
WHERE
    samp.[rnk] = 1

Which gives results:

Name                      Year        Month       Value       rnk
------------------------- ----------- ----------- ----------- ------
FRED                      2011        12          50          1
FRED                      2011        12          120         1
JERRY                     2012        9           100         1
JERRY                     2012        9           120         1
JERRY                     2012        9           130         1