Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8130239
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 6, 20262026-06-06T08:38:27+00:00 2026-06-06T08:38:27+00:00

select p.partnerid, sum(case when c.amount is not null then c.amount else 0 end) as

  • 0
select p.partnerid,
sum(case when c.amount is not null then c.amount else 0 end) as amount,
sum(case when c.netamt is not null then c.netamt else 0 end) as total,
sum(case when (c.netamt - d.paidamount) is not null then (c.netamt - d.paidamount) else 0 end) as remainingamount,
sum(case when d.paidamount is not null then d.paidamount else 0 end) as paidamt
from customerinfo c
left join dailypayments d on c.accno = d.accno
right join partnerinfo p on c.partnerid = p.partnerid
where (d.paiddate is null or (d.paiddate >= '2011-3-15' and d.paiddate <= '2012-6-13')) and  p.manager = 7 group by p.partnerid

from athe above query i need to subtract two values from two tables where there is no value in second table.

for better understanding see below image.

pic

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-06T08:38:31+00:00Added an answer on June 6, 2026 at 8:38 am

    Use the IFNULL() function to remove the case and simplify your calculation:

    sum(c.netamt - ifnull(d.paidamount, 0)) as remainingamount,
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

SELECT Wot.WorkOrderType, COUNT(CASE WHEN Wo.Status = 'C' THEN 1 END) as [Completed], COUNT(CASE WHEN
select 1 where somevalue = '' or somevalue is null from sometable I completely
SELECT plaka, party_id, sum(inf) i FROM party_sehir GROUP BY party_id, plaka This is my
SELECT distinct source_IP, timestamp FROM tb1 , tb2 WHERE tb1.source_IP not in ( SELECT
SELECT *, SUM(tbl.relevance) AS relevance FROM ( ( SELECT q_id, MATCH(a_content) AGAINST ('бутон') AS
select tag:- <%=select_tag names,options_from_collection_for_select(@users,id,name,@user.id)%> Right now my dropdown looks like this:- john matt sara
SELECT Ticket_id FROM Tickets WHERE Status = 1 AND (Ticket_id != ANY(array[1,2,3])) Limit 6
SELECT TO_DATE ( TO_CHAR (EXTRACT (MONTH FROM schedule.start_date)) || '-' || TO_CHAR (EXTRACT (DAY
SELECT d.sbjnum, d.name, d.scan_no, c.scanner FROM data AS d INNER JOIN check AS c
SELECT top 5 day_description, count(numberofdays) as number FROM mytable where department = 'departmentname' group

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.