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Home/ Questions/Q 6642251
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T23:54:31+00:00 2026-05-25T23:54:31+00:00

SELECT table1.PrimaryKey(Some ID), table2.nameOfSomething FROM table1 INNER JOIN table2 Here is the part i

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SELECT table1.PrimaryKey(Some ID), table2.nameOfSomething
FROM table1
INNER JOIN table2

Here is the part i don’t get :

USING(id)

this ID is table1 foreign key, and table2 primary key

i dont really get it..

table1.ID values:

25 Rows:

row 1-5 = 1 , row 6-10 = 2 , row 11-15  = 3 , row 16-20 = 4 , row 21-25 = 5

table2.ID values :

5 Rows:

row 1 = 1 , row 2 = 2 , row 3 = 3 , row 4 = 4 , row 5 = 5

i test it and i get different result without it, how comes?

Note : Table1 contains interests, Table2 contains categories for these interests

feel free to ask for more information

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T23:54:32+00:00Added an answer on May 25, 2026 at 11:54 pm
    |  Table1:   |   Table2:           |
    |  id        |   id  | table1_id   |
    |   1        |    1      3         |
    |   2        |    2      2         |
    |   3        |    3      1         |
    

    If you join the above two tables together with USING(id) it will match rows where the id value in Table1 are the same as the id value in Table2…

    SELECT * FROM table1 JOIN table2 USING(id)
    
    |  id   | id   table1_id  |
    |   1   |  1      3       |
    |   2   |  2      2       |
    |   3   |  3      1       |
    

    But, the id in Table2 might have nothing to do with the id in Table1. If that’s the case, you can use ON to be specific about how you match records together…

    SELECT * FROM table1 JOIN table2 ON table1.id = table2.table1_id
    
    |  id   | id   table1_id  |
    |   1   |  3      1       |
    |   2   |  2      2       |
    |   3   |  1      3       |
    

    If you specify nothing at all, you match every record in one table, against every record in the other table…

    SELECT * FROM table1 CROSS JOIN table2
    
    |  id   | id   table1_id  |
    |   1   |  1      3       |
    |   1   |  2      2       |
    |   1   |  3      1       |
    |   2   |  1      3       |
    |   2   |  2      2       |
    |   2   |  3      1       |
    |   3   |  1      3       |
    |   3   |  2      2       |
    |   3   |  3      1       |
    
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