Question

SELECT userid,SUBSTRING_INDEX(SUBSTRING_INDEX(data, '\"!', -1), '!\"', 1)+0 AS num 
FROM table
WHERE type=2
ORDER BY num DESC LIMIT 5

This picks up the number between !x! in a string and tries to return the number and order the rows by that number. It works fine.

However, I don’t know how to return unique user ids.

Adding ORDER BY userid returns the rows without ordering by num:

SELECT userid,SUBSTRING_INDEX(SUBSTRING_INDEX(data, '\"!', -1), '!\"', 1)+0 AS num 
FROM table
WHERE type=2
GROUP BY userid
ORDER BY num DESC LIMIT 5

Distinct doesn’t work either:

SELECT DISTINCT(userid),SUBSTRING_INDEX(SUBSTRING_INDEX(data, '\"!', -1), '!\"', 1)+0 AS num 
FROM table
WHERE type=2
ORDER BY num DESC LIMIT 5

I am out of ideas..

Example:

id    userid     data
1       56       !100!
2       22       !90!
3       56       !200!

Result should be:

userid      num
56          200
22          90

Answer 1

SELECT userid,MAX(num) num FROM
(SELECT userid,SUBSTRING_INDEX(SUBSTRING_INDEX(data, '\"!', -1), '!\"', 1)+0 AS num  
FROM table 
WHERE type=2) A
GROUP BY userid;