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Home/ Questions/Q 6835229
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T23:12:27+00:00 2026-05-26T23:12:27+00:00

// —sends an SMS message to another device— private void sendSMS(String phoneNumber, String message)

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// ---sends an SMS message to another device---
private void sendSMS(String phoneNumber, String message) {
    int i;
    SmsManager sms = SmsManager.getDefault();
    int amount = 10; // just making 10 the default if the EditText has an
                        // invalid value
    try {
        amount = Integer.parseInt(smsamount.getText().toString());
    } catch (NumberFormatException smsamount) {
    }

    for (i = 0; i < amount; i++) {

        if (amount < 100)
            sms.sendTextMessage(phoneNumber, null, message, null, null);

        else
            Toast.makeText(getBaseContext(),
                    "Please enter an amount less than 100.",
                    Toast.LENGTH_SHORT).show();
    }

}

This works, but the toast is staying on the screen for over a minute. It stays on the screen even after exiting the app. I have tried changing the toast to before the process to send the messages, but it force closes the app. Is this something that I am going to have to use the hack located here: http://thinkandroid.wordpress.com/2010/02/19/indefinite-toast-hack/ to make it shorter?

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  1. Editorial Team
    Editorial Team
    2026-05-26T23:12:27+00:00Added an answer on May 26, 2026 at 11:12 pm
    1. If you call N * 1 seconds Toasts at once, then they will sequentially display for up to ~N seconds, as that happens in your inner cycle. Here you get amount * SHORT_DURATION total duration of toasts.

    2. Do the condition checking if (amount < 100) before entering the loop. This is more correct, efficient, and will display only one Toast.

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