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Editorial Team
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Asked: 2026-05-14T21:15:30+00:00

setTimeout stack over flow.. $(document).ready(function(){ counterFN(); var theCounter = 1; function counterFN() { $(.searchInput).val(theCounter);

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setTimeout stack over flow..

$(document).ready(function(){
counterFN();

            var theCounter = 1;
            function counterFN()
            {
                $(".searchInput").val(theCounter);
                theCounter++;
                setTimeout(counterFN(),1000);    
            }

        });        
    </script>
</head>
<body>
    <input type="text" class="searchInput" />
</body> </html>
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1 Answer

  1. Editorial Team

    You are calling counterFN and setting its return value to run after 1000 milliseconds. Since you aren’t returning a function, you probably don’t want to do that.

    You probably want:

                setTimeout(counterFN,1000);

    Better yet, don’t be recursive, and do more caching of things that won’t change:

            var theCounter = 1;
        var input = $(".searchInput"); // Cache this
        function counterFN()
        {
            input.val(theCounter);
            theCounter++;
        }
        setInterval(counterFN, 1000);
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