Question

Setting format for the date

@String.Format("{0:D}", Model.Date)

Code above shows the date in the following format: (13 January 2012)

The required output: (Friday 13 January 2012)

Is there a format for this pattern?

Answer 1

Yep, here you go.

String.Format("{0:dddd d MMMM yyyy}", Model.Date)

Full MSDN Documentation

The general rule I use to remember these formats is like this:

one character means the number alone;
two characters means add a leading zero if necessary
three characters means use three letters if day or month, four numbers for year
four letters means use full word for day or month
Extra stuff (not special characters) just gets put in the string

e.g. Consider 1st Jan 2001

String.Format("{0:(d;dd;ddd;dddd),(M;MM;MMM;MMMM),(y,yy,yyy,yyyy)}", DateTime.Parse("2001/01/01"))

will return

(1;01;Mon;Monday),(1;01;Jan;January),(1,01,2001,2001)

Similar rules for times, like this:

String.Format("{0:(h;hh):(m;mm):(s,ss) (t,tt)}", DateTime.Now)

to give this:

(9;09):(41;41):(34,34) (P,PM)