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Home/ Questions/Q 8217723
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T12:33:06+00:00 2026-06-07T12:33:06+00:00

Setting up a search page with Django Haystack involves putting in their URLconf snippet

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Setting up a search page with Django Haystack involves putting in their URLconf snippet url(r'^search/', include('haystack.urls')). However, this means (at least from my extremely basic understanding of Django/MVC), that there is no simple way to pass extra context (i.e. an extra dictionary key/value) to be rendered onto the page.

In particular, I want to customize a search field to mirror the variable passed onto the page from a GET request:

<form method="get" action=".">
<input type="text" name="q" value="">
<!-- result html here -->
</form>

Say the parameter ?q=twitter is attached to the URL as part of a GET request; I’d like to make the value selector equal to twitter. If I had control of the view, I would likely do it something like this:

if request.method == 'GET':
    q = request.GET['q']
    return render(request, 'template.html', {'q': q})

And then use q as the value for the value selector in the HTML <input>.

Is there any way to accomplish this in a simple manner, besides editing the Haystack source?

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  1. Editorial Team
    Editorial Team
    2026-06-07T12:33:07+00:00Added an answer on June 7, 2026 at 12:33 pm

    Accomplished this using a custom context processor:

    from django.template import RequestContext
    from django.http import HttpResponse
    
    def get_search_query(request):
        search_query = request.GET.get('q', '')
        print search_query
        return {
            'search_query':search_query
        }
    

    Then, simply call {{ search_query }} in any of your HTML templates.

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