Question

Should be easy, but somehow I don’t get it. I want to apply a given function. Background is copy a class and applying a given method on the newly created copy.

Major Edit. Sorry for that.

   import copy
   class A:

       def foo(self,funcName):
           print 'foo'
           funcName()

       def Bar(self):
           print 'Bar'

        def copyApply(self,funcName):
           cpy = copy.copy()
           # apply funcName to cpy??

    a = A()
    func = a.Bar()
    a.foo(func) # output 'Bar'
    b = a.copyApply(foo) # new copy with applied foo

Answer 1

Note that your A.foo does not take the name of a function, but the function itself.

class A:
   def bar(self):
       print 'Bar'

   def apply(self, func):
       func()  # call it like any other function

   def copyApply(self, func):
       cpy = copy.copy(self)
       func(cpy)  # cpy becomes the self parameter

a = A()
func = a.bar  # don't call the function yet

a.apply(func)       # call the bound method `a.bar`
a.apply(a.bar)      # same as the line above
a.copyApply(A.bar)  # call the unbound method `A.bar` on a new `A`

In python, a.foo() is the same as A.foo(a), where a is of type A. Therefore, your copyApply method takes the unbound bar method as its argument, whereas foo takes a bound method.