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Home/ Questions/Q 7922407
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T16:56:32+00:00 2026-06-03T16:56:32+00:00

Should be easy. I’m adding a button to each table row, that gets information

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Should be easy. I’m adding a button to each table row, that gets information out of a number of table cells in that row.

<tr>
  <td><img src='targetInfo' /></td>
  <td></td>
  <td>
    <div>CLICKED ELEMENT</div>
  </td>
</tr>

I would expect:

this: $(this).closest('tr td:eq(0) img').attr('src'); or

this: $(this).closest('tr>td:eq(0)>img').attr('src');

to work, but neither is working properly.

Currently I’m having to use the below, which seems sub-optimal. What am I missing in my selector?

$(this).closest('tr').children('td:eq(0)').children('img').attr('src');
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T16:56:35+00:00Added an answer on June 3, 2026 at 4:56 pm

    Your current working solution is the best approach (or something similar to it, such as):

    $(this).closest('tr').children('td:eq(0) > img').attr('src');
    

    For this problem you won’t be able to avoid having to crawl up the tree and then back down. Several ways to accomplish that, but not within a single selector.

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