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Home/ Questions/Q 4236286
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T02:37:03+00:00 2026-05-21T02:37:03+00:00

signed long long value = -2147483648; cout << ((signed long long)value); outputs 2147483648 (no

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signed long long value = -2147483648;
    cout << ((signed long long)value);

outputs 2147483648 (no minus sign), why?

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  1. Editorial Team
    Editorial Team
    2026-05-21T02:37:04+00:00Added an answer on May 21, 2026 at 2:37 am
    signed long long value = -2147483648;
    

    2147483648 cannot be represented in a 32-bit signed integer, so it is converted to an unsigned, then unary minus is applied (which doesn’t change anything), and then it is assigned to the signed long long. Use -2147483648LL

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