Question

Simple question for a newb and my Google-Fu is failing me. Using PHP, how can you count the number of files in a given directory, including any sub-directories (and any sub-directories they might have, etc.)? e.g. if directory structure looks like this:

 /Dir_A/   /Dir_A/File1.blah   /Dir_A/Dir_B/   /Dir_A/Dir_B/File2.blah   /Dir_A/Dir_B/File3.blah   /Dir_A/Dir_B/Dir_C/   /Dir_A/Dir_B/Dir_C/File4.blah   /Dir_A/Dir_D/   /Dir_A/Dir_D/File5.blah 

The script should return with ‘5’ for ‘./Dir_A’.

I’ve cobbled together the following but it’s not quite returning the correct answer, and I’m not sure why:

 function getFilecount( $path = '.', $filecount = 0, $total = 0 ){       $ignore = array( 'cgi-bin', '.', '..', '.DS_Store' );       $dh = @opendir( $path );       while( false !== ( $file = readdir( $dh ) ) ){           if( !in_array( $file, $ignore ) ){               if( is_dir( '$path/$file' ) ){                   $filecount = count(glob( '$path/$file/' . '*'));                   $total += $filecount;                   echo $filecount; /* debugging */                 echo ' $total'; /* debugging */                 echo ' $path/$file
'; /* debugging */                 getFilecount( '$path/$file', $filecount, $total);               }           }       }       return $total;   }   

I’d greatly appreciate any help.

Answer 1

This should do the trick:

function getFileCount($path) {     $size = 0;     $ignore = array('.','..','cgi-bin','.DS_Store');     $files = scandir($path);     foreach($files as $t) {         if(in_array($t, $ignore)) continue;         if (is_dir(rtrim($path, '/') . '/' . $t)) {             $size += getFileCount(rtrim($path, '/') . '/' . $t);         } else {             $size++;         }        }     return $size; }