Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
SimpleDateFormat pattern is “yyyyMM”, and the arg is yyyy-MM, but there are no exception and a wrong result. why? thx~~
SimpleDateFormat format = new SimpleDateFormat("yyyyMM");
System.out.println(format.format(format.parse("2011-07")));
the result is 201105
Use
setLenient(false); it will then throw the exception you expect.See the setLenient() docs.