Question

Simply, is

&someObject->someAttribute.someMember;

equivalent to

&(someObject->someAttribute.someMember);

or

(&someObject)->someAttribute.someMember;

or

(&(someObject->someAttribute)).someMember;

Or should you really put explicit parenthesis there just to be safe?

Answer 1

It is equivalent to:

&((someObject->someAttribute).someMember)

The -> and . have equal precedence and are left-associative. The unary-& has lower precedence.

If you have very complex expressions, then you should certainly use parentheses to group things and clarify your code. This isn’t particularly complex, though; it is quite common to see code like this in C and C++.