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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T00:19:11+00:00 2026-06-07T00:19:11+00:00

since memcpy should be highly optimized nowadays, does it still make sense to optimize

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since memcpy should be highly optimized nowadays, does it still make sense to optimize the copy of Ipv6 addresses using explicit loop unrolling ?

#include <netinet/in.h>

struct in6_addr IP_1;
struct in6_addr IP_2;
;
;
IP2.__in6_u.__u6_addr32[0] = IP1.__in6_u.__u6_addr32[0];
IP2.__in6_u.__u6_addr32[1] = IP1.__in6_u.__u6_addr32[1];
IP2.__in6_u.__u6_addr32[2] = IP1.__in6_u.__u6_addr32[2];
IP2.__in6_u.__u6_addr32[3] = IP1.__in6_u.__u6_addr32[3];

Note that the code above is best suited for 32-bit architectures.

Is there a best practice I do not know ?

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  1. Editorial Team
    Editorial Team
    2026-06-07T00:19:12+00:00Added an answer on June 7, 2026 at 12:19 am

    You should just do IP2 = IP1;, and let the compiler deal with it.

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