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Home/ Questions/Q 6853663
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T01:32:20+00:00 2026-05-27T01:32:20+00:00

Since the play documentation on models is terrible I’ll ask here. I have the

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Since the play documentation on models is terrible I’ll ask here. I have the basic code;

public static void Controller() {
        List<Item> item = Item.find("SELECT itemname,id FROM Item WHERE itembool = true ORDER BY itemcreated ASC LIMIT 0,1").fetch();
        
        if ( item == null ) {
            notFound();
        }
    }

What I’m trying to do is get the value for ‘itemname’ returned for the first value returned from an SQL query (The real query is much more complicated and other things so it can’t be replaced with methods). I can get the entire first object with item.get(0) but I can’t figure out how to get the value of ‘itemname’ as a string and it doesn’t seem to be documented anywhere.

Edit

Probably should have mentioned in the original question, I need to retrieve by field name, not index. I.E. I can’t do items.get(0)[0]; I need to do items.get(0)['itemname'];

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  1. Editorial Team
    Editorial Team
    2026-05-27T01:32:20+00:00Added an answer on May 27, 2026 at 1:32 am

    The documentation explains this if you read it, in here. Hibernate doesn’t use SQL, but JPQL, which has a different syntax as it works with objects, not individual fields.

    What you want to do can be achieved in two ways (both in the documentation):

    List<Item> item = Item.find("SELECT i FROM Item i WHERE i.itembool = true ORDER BY i.itemcreated ASC").fetch(1);
    
    List<Item> item = Item.find("itembool = true ORDER BY itemcreated ASC").fetch(1);
    

    EDIT:

    On the retrieval part, you will get a list of Item, so you can just access the field directly on the object:

    item.get(0).getItemName();
    
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