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Home/ Questions/Q 9143453
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T10:01:50+00:00 2026-06-17T10:01:50+00:00

Since you can take integral values as template parameters and perform arithmetic on them,

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Since you can take integral values as template parameters and perform arithmetic on them, what’s the motivation behind boost::mpl::int_<> and other integral constants? Does this motivation still apply in C++11?

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  1. Editorial Team
    Editorial Team
    2026-06-17T10:01:51+00:00Added an answer on June 17, 2026 at 10:01 am

    You can take integral values as template parameters, but you cannot take both types and non-type template parameters with a single template. Long story short, treating non-type template parameters as types allows for them to be used with a myriad of things within MPL.

    For instance, consider a metafunction find that works with types and looks for an equal type within a sequence. If you wished to use it with non-type template parameters you would need to reimplement new algorithms ‘overloads’, a find_c for which you have to manually specify the type of the integral value. Now imagine you want it to work with mixed integral types as the rest of the language does, or that you want to mix types and non-types, you get an explosion of ‘overloads’ that also happen to be harder to use as you have to specify the type of each non-type parameter everywhere.

    This motivation does still apply in C++11.

    This motivation will still apply to C++y and any other version, unless we have some new rule that allows conversion from non-type template parameters to type template parameters. For instance, whenever you use 5 and the template requests a type instantiate it with std::integral_constant< int, 5 > instead.

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