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Editorial Team
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Asked: 2026-06-13T13:13:36+00:00

Situation In my alarm clock app I start a NewAlarmActivity by clicking a button.

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Situation

In my alarm clock app I start a NewAlarmActivity by clicking a button.
After the user has made all the selections, alarm gets set and `finish() is called.

The matter

I create a new LinearLayout object with images and text within it. That layout must be added to the screen of previous activity (to another LinearLayout placed inside a ScrollView) so the user is able to see the alarm set. Somehow I have to pass that LinearLayout object to the first activity and tell it to receive and add the object to the screen.

How can I do that?

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1 Answer

  1. Editorial Team

    You just need to read some documentation about startActivityForResult().

    BTW, IMHO, you should not transport your LinearLayout object between activities, that’s ugly.

    How to manage `startActivityForResult` on Android?

    Starting Activity And Getting Result

    This has been asked countless times…

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