Question

So basically I got string array, lets say a[i][b];

so the code looks something like this –

for(int i = 0; i < 3; i++) {
  for(int n = 0; b < 3; b++) {
    if(a[i][b] == "s") {
     cout << a[i][b] << endl;
    }
  }
}

the array exists, and I can check it if I just show on console the a[i][b] without if statement, but with if statement it gives me this error –

error: ISO C++ forbids comparison between pointer and integer

Is there any way to fix that?

Answer 1

“s” is a string literal, i.e. a character array, so decays to a pointer. To just compare to a character, use single quotes:

if (a[i][b]=='s')