Question

So basically I have been trying to insert columns into my third table from columns extracted from 2 tables in prior.

I have one info table which stores information of users,
one image table which stores head photos of users,
and one id table which is like a reference table,designed to display correct head photos associated to correct users when necessary(like user querying or simply displaying…)

My code:

$result_1 = mysql_query("SELECT info_id FROM info WHERE info_name = '$_POST[name]'");
$result_2 = mysql_query("SELECT image_id FROM image WHERE image_name = '$_FILES[file][name]'");
$sql = "INSERT INTO id_table (main_id, id_info, id_image)
         VALUES (NULL, $result_1, $result_2);";
if(!mysql_query($sql,$connect_database)){
   die('Error: ',mysql_error());
}

So the codes above simply illustrated my idea:
1. get the id of info from info table
2. get the id of image from image table
3. insert both ids into columns in id_table respectively

Then I got this error information:

Error: You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near ‘id #4, Resource id #5 )’ at line 1

I could not figure out where the problem is…

Answer 1

$result_1 and$result_2 just contain pointers to the results. you still have to loop through them to get the actual values.

Try this:

$result_1 = mysql_query("SELECT info_id FROM info WHERE info_name = '$_POST[name]'");
$row1 = mysql_fetch_array($result_1); // get 1st result row

$result_2 = mysql_query("SELECT image_id FROM image WHERE image_name = '$_FILES[file][name]'");
$row2 = mysql_fetch_array($result_2); // get 2nd result row

$sql = "INSERT INTO id_table (main_id, id_info, id_image)
         VALUES (NULL, '{$row1['info_id']}', '{$row1['image_id']}');";
if(!mysql_query($sql,$connect_database)){
   die('Error: ',mysql_error());
}