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Home/ Questions/Q 6333065
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T18:23:22+00:00 2026-05-24T18:23:22+00:00

So basically I have this XML Doc <?xml version=1.0 encoding=utf-8 ?> <items> <food> <item

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So basically I have this XML Doc

<?xml version="1.0" encoding="utf-8" ?>
<items>
  <food>
    <item ItemName="Hamburger" Cost="1.50" Image="hamburger.jpg" />
    <item ItemName="Hamburger" Cost="1.50" Image="hamburger.jpg" />
    <item ItemName="Hamburger" Cost="1.50" Image="hamburger.jpg" />
    <item ItemName="Hamburger" Cost="1.50" Image="hamburger.jpg" />
  </food>
  <snaks>

  </snaks>
  <drinks>
    <item ItemName="Hamburger" Cost="1.50" Image="hamburger.jpg" />
    <item ItemName="Hamburger" Cost="1.50" Image="hamburger.jpg" />
    <item ItemName="Hamburger" Cost="1.50" Image="hamburger.jpg" />
  </drinks>
  <vitamins>

  </vitamins>
</items>

I want to be able to load the Attributes of <item> in <items><food> and do something with with each <item>. I tried something like this (This) but it only worked for the first <item> not the other 3.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T18:23:23+00:00Added an answer on May 24, 2026 at 6:23 pm

    I’d use XmlSerializer and define an object matching the document. Something like this:

    public class Item
    {
      [XmlAttribute("ItemName")]
      public string Name { get; set; }   
    
      [XmlAttribute("Cost")]
      public decimal Cost { get; set; }   
    
      [XmlAttribute("Image")]
      public decimal Image { get; set; }   
    }
    
    [XmlRoot("items")]
    public class Items
    {
      [XmlArray("food")]
      [XmlArrayItem("item")]
      public List<Item> Food { get; set; }
    
      [XmlArray("snaks")]
      [XmlArrayItem("item")]
      public List<Item> Snacks { get; set; }
    
      [XmlArray("drinks")]
      [XmlArrayItem("item")]
      public List<Item> Drinks { get; set; }     
    
      [XmlArray("vitamins")]
      [XmlArrayItem("item")]
      public List<Item> Vitamins { get; set; }
    }
    

    Use it like this:

    public class Example
    {
      static void Main()
      {
         using (Stream s = File.OpenRead("myfile.xml"))
         {
            Items myItems = (Items) new XmlSerializer(typeof (Items)).Deserialize(s);
         }
      }
    }
    
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