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Home/ Questions/Q 8574177
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T19:24:57+00:00 2026-06-11T19:24:57+00:00

So basically I’m using jQuery ui prgoressbar and I’d like to print all the

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So basically I’m using jQuery ui prgoressbar and I’d like to print all the values. Here is the code:

    $(function() {

        var a = $('.progressbar.item1').progressbar({value: 37});
        var b = $('.progressbar.item2').progressbar({value: 55});
        var c = $('.progressbar.item3').progressbar({value: 99});
        ...
        var x = $('.progressbar.itemx').progressbar({value: 29});

        $(a).find('.ui-progressbar-value').append('<span>' + a.progressbar('option','value') + '%</span>');
        $(b).find('.ui-progressbar-value').append('<span>' + b.progressbar('option','value') + '%</span>');
        $(c).find('.ui-progressbar-value').append('<span>' + c.progressbar('option','value') + '%</span>');
        ...
        $(x).find('.ui-progressbar-value').append('<span>' + x.progressbar('option','value') + '%</span>');

    });

How can I achieve to make it shorter like using ‘for’ of ‘each’? Thanks.

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  1. Editorial Team
    Editorial Team
    2026-06-11T19:24:58+00:00Added an answer on June 11, 2026 at 7:24 pm

    Try building an object filled with the progress bars:

    $(function() {
    
        var classes_values = {
            '.item1' : 37,
            '.item2' : 55,
            '.item3' : 99,
            '.itemx' : 29
        };
    
        var progress_bars = {};
    
        $.each(classes_values, function(class, value){          
            progress_bars[class] = 
                $('.progressbar'+class).progressbar({'value' : value});                     
        });
    
        $.each(progress_bars, function(class, progress_bar){                        
            $('.ui-progressbar-value', progress_bar).append(
                '<span>' + progress_bar.progressbar('option','value') + '%</span>');        
        });
    
    });
    
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