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Home/ Questions/Q 6337541
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T19:16:16+00:00 2026-05-24T19:16:16+00:00

So here is my code, have no ide why its not working have been

  • 0

So here is my code, have no ide why its not working have been looking at it for hours, points to anyone who can figure it out. The variables are passed fine, and server connection made. The error message the browser gives is,

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘username”, ‘Saturday 20th of August 2011 02:02:22 PM’, ‘first’, ‘last’, ‘ssn’ at line 2

i replaced the variable data back with the variable name so you can get an idea, so where is says first, the browser actually shows the first name i entered.

Thanks!

$HTTP_COOKIE_VARS['username'] = $username;
$email = $_REQUEST['email'];
 $Todaysdate = date('l jS \of F Y h:i:s A');
 $firstname = $_REQUEST['firstname'];
 $lastname = $_REQUEST['lastname'];
 $ssn = $_REQUEST['ssn'];  
 $street = $_REQUEST['street']; 
 $city = $_REQUEST['city'];
 $zip = $_REQUEST['zip'];
 $phone1 = $_REQUEST['phone1'];
 $phone2 = $_REQUEST['phone2']; 
 $hdhas = $_REQUEST['hdhas'];
 $mi= $_REQUEST['mi'];





 $query = ("INSERT INTO Members (username, email, todaysdate, firstname, lastname, ssn,       street, city, zip, phone1, phone2, hdhas, mi)
 VALUES('$username','$email', '$Todaysdate', '$firstname', '$lastname', '$ssn', '$street', '$city', '$zip', '$phone1', '$phone2', '$hdhas', '$mi')");



 $checkuser = mysql_query("SELECT username FROM Members WHERE username='$username'"); 


 if(mysql_num_rows($checkuser)>0)
{
 mysql_query("UPDATE Members SET email='$email', username='$username', todaysdate='$Todaysdate', firstname='$firstname', lastname='$lastname', ssn='$ssn',  street='$street', city='$city', zip='$zip', phone1='$phone1', phone2='$phone2',  hdhas='$hdhas', mi='$mi' WHERE username = '$username'");
 } 

else {
mysql_query($query);
}

mysql_query($query) or die(mysql_error());
mysql_close();
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  1. Editorial Team
    Editorial Team
    2026-05-24T19:16:17+00:00Added an answer on May 24, 2026 at 7:16 pm

    Username is probably username'. Try to add mysql_real_escape_string() around your variables and read about SQL Injection

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