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Home/ Questions/Q 8356397
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T10:11:11+00:00 2026-06-09T10:11:11+00:00

So, here’s my situation : I’m getting some input stored in a variable (

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So, here’s my situation :

I’m getting some input stored in a variable ($keywords).
This variable may either be a string (=1 keyword) – like "banana", or it may be an array (=multiple keywords) – like array ("banana","apple","mango").

This is the way I’m using it :

foreach ($keywords as $keyword)
{
    // do sth with $keyword
}

This works fine when $keyword is an array, but when it’s not I’m getting errors. (quite obviously)

What would be the most efficient workaround, to avoid errors, while keeping my foreach structure as-is?


This is what I’ve thought of (to put before the loop), but I don’t really like it :

if (count($keywords)==1) $keywords = array($keywords);

UPDATE : Guys, I know about is_array. My point was to do it as elegantly as possible, without adding block of code or creating a mess with switch or if/else statements, etc.

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  1. Editorial Team
    Editorial Team
    2026-06-09T10:11:12+00:00Added an answer on June 9, 2026 at 10:11 am

    simply cast the variable to array:

    $keywords = (array) $keywords;
    

    if the variable is an array no thing will happen , otherwise it will be transformed to an array :
    so
    1 will be array(1)
    AND
    'keyword' will be array('keyword')

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