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Home/ Questions/Q 6471003
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T06:10:29+00:00 2026-05-25T06:10:29+00:00

So I am starting to get into Android development with really basic applications. I’m

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So I am starting to get into Android development with really basic applications. I’m messing around with AlertDialogs and am trying to get a list view working. I have a button that when clicked should call a function to create/display the AlertDialog. Here is the code for the button.

<Button android:layout_height="wrap_content" android:text="@string/partyChoice" android:id="@+id/partyChoiceButton" android:layout_width="wrap_content" android:layout_above="@+id/shirtSizeButton" android:layout_alignParentLeft="true" android:layout_alignParentRight="true" android:onClick="partyChoice">

And here is the code for the function partyChoice

public void partyChoice()
{
    final CharSequence[] items = {"Bowling", "Laser Tag", "Combo", "Cosmic"};

    AlertDialog.Builder builder = new AlertDialog.Builder(PartyPlannerActivity.this);
    builder.setTitle("Choose A Party");
    //builder.setIcon(R.drawable.icon);
    builder.setSingleChoiceItems(items, -1, new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int item) {
     Toast.makeText(getApplicationContext(), items[item], Toast.LENGTH_SHORT).show();
        }
    });

    builder.setPositiveButton("Yes",
     new DialogInterface.OnClickListener() {
      public void onClick(DialogInterface dialog, int id) {
       Toast.makeText(PartyPlannerActivity.this, "Success", Toast.LENGTH_SHORT).show();
      }
     });
    builder.setNegativeButton("No",
     new DialogInterface.OnClickListener() {
      public void onClick(DialogInterface dialog, int id) {
       Toast.makeText(PartyPlannerActivity.this, "Fail", Toast.LENGTH_SHORT).show();
      }
     });
    AlertDialog alert = builder.create();
    alert.show();
}

This code compiles and runs with no errors, however when I go to click the button, my application force closes. I cannot find where the issue is. If anyone could help me it would be greatly appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T06:10:30+00:00Added an answer on May 25, 2026 at 6:10 am

    All onClick functions which are referenced from XML have to take a View argument.

    Change

    public void partyChoice()
    

    to

    public void partyChoice(View v)
    
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