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Home/ Questions/Q 542671
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:28:16+00:00 2026-05-13T10:28:16+00:00

So I am using HtmlUnit, and the method’s signature looks like: public HtmlAnchor getAnchorByText(String

  • 0

So I am using HtmlUnit, and the method’s signature looks like:

public HtmlAnchor getAnchorByText(String text)
                           throws ElementNotFoundException

So this means, the call to this method won’t just return null, but it will throw an exception.

(I find this a pain!!, in c# methods usually just return a null if not found, way easier unless I am missing something??)

So I HAVE to wrap this call in an exception if I don’t want my application to crash right?

How do I do this in Java?

reference: http://htmlunit.sourceforge.net/apidocs/index.html

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T10:28:17+00:00Added an answer on May 13, 2026 at 10:28 am

    Bear in mind that ElementNotFoundException is not a checked exception so you could ignore it. But if the element not being there is a valid case that you don’t want an exception thrown in then yes you will have to wrap the code in a try-catch block and deal with it.

    I too find this kind of flow-control-by-exceptions painful. The basic construct you want is:

    HtmlAnchor anchor = null;
    try {
      htmlAnchor = getAnchorByText(text);
    } catch (ElementNotFoundException) {
      // do nothing
    }
    

    If you find yourself writing this sequence a lot then wrap it in a helper method:

    public static HtmlAnchor myFindAnchor(String text) {
      try {
        return getAnchorByText(text);
      } catch (ElementNotFoundException) {
        return null;
      }
    }
    

    and call that instead of littering your code with spurious try-catch blocks.

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