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Home/ Questions/Q 7407175
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T05:40:16+00:00 2026-05-29T05:40:16+00:00

So i basically need my program to open a file and do something. When

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So i basically need my program to open a file and do something. When the program asks for the user to input the file name, and the user inputs the name of file correctly the first time, the operation works. But if the user typed the name wrong, the program says “invalid name try again” but then it is never able to open the file even if the user types the name correctly. Here’s the code:

ifstream read_file(file.c_str());
while(true)
{
    if(!(read_file.fail()))
    { 
        ...
    }
    else 
    {
        cout << "Either the file doesn't exist or the formatting of the file is incorrect. Try again.\n>";
    }
    cin >> file;
    ifstream read_file(file.c_str());
}

What is the problem, any thoughts? Thank you

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T05:40:16+00:00Added an answer on May 29, 2026 at 5:40 am

    You are redeclaring read_file inside the loop, but the code at the top of the loop always use the read_file outside the loop.

    This is what you want instead:

    ifstream read_file(file.c_str());
    while(true)
    {
        if(!(read_file.fail()))
        { 
            ...
        }
        else 
        {
            cout << "Either the file doesn't exist or the formatting of the file is incorrect. Try again.\n>";
        }
        cin >> file;
        read_file.open(file.c_str()); /// <<< this has changed
    }
    
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