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Home/ Questions/Q 9259291
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T12:37:15+00:00 2026-06-18T12:37:15+00:00

So I can do one call to get all friends. then iterate through and

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So I can do one call to get all friends.
then iterate through and get albums for each friend.

the api/network overhead is insane as usually friend counts are super high.

is there anyway to get all the albums directly in that same original user.friends() call?

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  1. Editorial Team
    Editorial Team
    2026-06-18T12:37:16+00:00Added an answer on June 18, 2026 at 12:37 pm

    Field expansion is your friend. Try this:

    me/friends?fields=albums
    

    If you’ve got a lot of friends, running this query could take some time.

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