Question

So I created a custom int.tryparse method in c# to try to make things a little easier and cleaner looking. Here is the method:

    public static int? BoolIntParse(string number)
    {
        int temp;
        if (int.TryParse(number, out temp))
            return temp;
        else
            return null;
    }

Now, I would like to try to use it in this fashion:

if(int? someNumber = BoolIntParse(someString))
{
    //do some stuff if its a number
}
else
   //throw some error 

Which doesn’t seem to work. I also tried assigning the value before the condtional such as:

int? someNumber = BoolIntParse(someString);
if(someNumber)
{
    //do some stuff if its a number
}
else
   //throw some error 

And I get the error message Cannot implicitely convert type int? to bool

So this isn’t legal c#. Is this what a nullible int was designed for (this type of situation) or am I just not doing it correctly? I’m relatively new to c#.

Answer 1

You want to check if someNumber.HasValue. That should be in your conditional.

if (someNumber.HasValue)

or as an alternative, mentioned by @BrokenGlass:

if (someNumber != null)