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Home/ Questions/Q 9224531
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T04:20:43+00:00 2026-06-18T04:20:43+00:00

So I currently have some code similar to this: (Note: not actual code, just

  • 0

So I currently have some code similar to this:

(Note: not actual code, just pared down from a somewhat long and complex method for brevity.)

template<typename ArgT0, typename ArgT1, typename FuncT>
static void addMethod( const std::string& name, FuncT func )
{
   Method script_func = [&]( const Arguments& args ) -> Value
   {
      func(UnsafeAnyCast<ArgT0>(args[0]),UnsafeAnyCast<ArgT1>(args[1]));
      return Value::Undefined();
   }

   _prototype->Set( name, script_func );
}

It works fine in Visual Studio 2010, but I know that is far from any guarantee that it is standard compliant C++. Is there anything wrong with this as far as using the template arguments inside the lambda?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T04:20:45+00:00Added an answer on June 18, 2026 at 4:20 am

    Yes, this is standard compliant: a lambda expression has access to all the visible names in its enclosing scope, it’s only variables that you need to capture

    5.1.2 Lambda expressions [expr.prim.lambda]

    9 A lambda-expression whose smallest enclosing scope is a block scope
    (3.3.3) is a local lambda expression; any other lambda-expression
    shall not have a capture-list in its lambda-introducer. The reaching
    scope of a local lambda expression is the set of enclosing scopes up
    to and including the innermost enclosing function and its parameters

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