Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7600307
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 30, 20262026-05-30T22:52:45+00:00 2026-05-30T22:52:45+00:00

So I got the following scenario: $(‘.menu’).find(‘a’).each( function(el, val) { if( window.location.hash !== val.hash

  • 0

So I got the following scenario:

$('.menu').find('a').each( function(el, val) {
  if( window.location.hash !== val.hash ) {
    $('.menu li').first().addClass('active') // we found no valid hash for us, so set first <li> active
    $('#hash1').show() // and show the first content
  } else {
    $(this).parent().addClass('active') // we found an hash, so give its parent <li> an active class
    $(window.location.hash).show() // can be #hash2, #hash3, whatever
    return false; // since we found something, stop the if.
  }
});

Well now obviously, each time we found no valid hash, we set the first element active and show the first content… but I dont want that.

I want the if to loop through all elements first before we go into the else statement.. and THEN if we found nothing, set the first element active and show the first content.

since I am looping through each “a”, how do I do that?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-30T22:52:46+00:00Added an answer on May 30, 2026 at 10:52 pm

    You can use .filter() to get the elements you want. If none are selected, you perform the default action:

    var $links = $('.menu').find('a').filter(function() {
        return window.location.hash === this.hash;
    });
    
    if($links.length > 0) {
        $links.parent().addClass('active');
        $(window.location.hash).show();
    }
    else {
        $('.menu li').first().addClass('active');
        $('#hash1').show();
    }
    

    Reference: .filter

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I got the following webpage-builtup: <div id=menu> </div> <div id=content> <!-- you just need
I got the following scenario: I am writing an app, which acts like a
I have the following scenario: User X logs in to the application from location
I got the above mentioned exception when performing following scenario. Students and Address have
I've got a scenario like the following: class criterion { // stuff about criteria...
I've got the following scenario: User has the ability to drag-and-drop a control onto
I got a little problem here guys. I'm trying to implement the following scenario:
I have got the following scenario. In my SL application, I am getting some
I got into another philosophical question regarding Java. It's about the following scenario: You
I got stuck with the following scenario like I have two timers. If user

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.