Question

So I have a bunch of strings in records that include the ‘/’ character, eg:

RECORD_NAME
Foo bar
Foo/bar
Fo/o/bar

And several million records.

I’m wanting to say, count the number of records with 2 ‘/’ characters.

So to look for one, I’d do, say:

select count(*) from my_table where record_name like '%[/]%'

Which would presumably get all the ones with one ‘/’ in there.

How do I go about counting the ones with say, two forward slashes? Can you include regular expressions in a SQL query?

Answer 1

this should work:

select count(*) from my_table where record_name like '%/%/%' and record_name not like '%/%/%/%'

This way you will always include the rows with two //, but if got three or more, the not like will avoid them