So I have a form that looks so.
<form action="thanks.php" method="post" class="niceform" name="myform">
<table>
<tr>
<td><label for="company_name">Company Name</label></td>
<td><input type="text" name="company" value="" size="38" /></td>
</tr>
// and so on
I have the validation by javascript. But the problem is that when I go directly to thanks.php from localhost/mysite/form/thanks.php I have an empty row that is inserted when I look at phpmyadmin. Thanks.php looks like so.
<?php
// open the connection
$conn = mysql_connect("localhost", "root", "password");
// pick the database to use
mysql_select_db("company_register",$conn);
$sql = "INSERT INTO `tblsignups` VALUES ('NULL', '$_POST[company]', '$_POST[email]', '$_POST[phone]', '$_POST[address]', '$_POST[comments]', '$_POST[contact_person]')";
$result = mysql_query($sql, $conn) or die(mysql_error());
mysql_close($conn);
?>
// And I have a thank you msg I display
How do I check that if some one should directly go to thanks.php I tell them to go fill the form first and do not put anything on the database
here is a sketch example
after receiving POST data you have to check it and raise error flag
in case of some errors show the form back instead of saving it
and modify your form to make it possible to show errors