Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7055623
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T03:46:17+00:00 2026-05-28T03:46:17+00:00

So I have a page with a jquery ui slider on it initialized with

  • 0

So I have a page with a jquery ui slider on it initialized with the following:

var min = $("#attrInformation").data("lowest_price"),
max = $("#attrInformation").data("highest_price");

    $( "#slider-range" ).slider({
        range: true,
        min: min,
        max: max,
        values: [ min, max ],
        slide: function( event, ui ) {
            var start = ui.values[0],
            end = ui.values[1];

            $("#startPrice").text(start);
            $("#endPrice").text(end);
        },
        stop: function(event,ui){
            var start = ui.values[0],
            end = ui.values[1];

            refineObject.price_min = start;
            refineObject.price_max = end;

            refineResults(refineObject);
        }
    });

and i want to be able to change the min, max, AND the value for which the two handles are on based on the results of an ajax call. so i’ve tried something like this:

    $.get("ajax.php",options,function(data){
    $('.middle_container').html(data);          

    $('#slider-range').slider( "option", "min", $('.middle_container').find('.start_price').val() );
    $('#slider-range').slider( "option", "max", $('.middle_container').find('.end_price').val() );
    $('#slider-range').slider("value", $('#slider-range').slider("value"));

        });

where my min and max are contained in two hidden divs with the class start_price and end_price. this currently does not work, it doesn’t update the max price and the slider’s right handle appears over on the left out of position. any suggestions on how to make this work? i’m using php for the backend. the start_price and end_price code is working and correct.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-28T03:46:17+00:00Added an answer on May 28, 2026 at 3:46 am

    Make sure $('.middle_container').find('.start_price').val() and $('.middle_container').find('.end_price').val() are returning proper values. Also to set the value of the slider you have to use the same syntax which you are using for setting min/max values. Also

    Try this

    $.get("ajax.php",options,function(data){
        $('.middle_container').html(data);          
    
        $('#slider-range').slider( "option", "min", $('.middle_container').find('.start_price').val() );
        $('#slider-range').slider( "option", "max", $('.middle_container').find('.end_price').val() );
        $('#slider-range').slider( "option", "value", $('#slider-range').slider("value"));
    
    });
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a page which contains a jQuery-UI horizontal slider, created using a little
I have a jquery based slider on the page. This slider calls a function
I have a jquery Image slider in a content page that worked fine. Once
I have an absolute positioned jQuery slider on my page. With it, I want
I have a page that has multiple sliders (from http://www.switchonthecode.com/tutorials/using-jquery-slider-to-scroll-a-div ) and since each
I have several jQuery-ui range sliders on a page which add and remove rows
I have a page that uses jQuery with a small glitch. I managed to
I have a jQuery UI Dialog working great on my ASP.NET page: jQuery(function() {
I have a page being loaded with jQuery. The initial load includes 100 records
I have a web page that uses jquery ajax to grab the table markup

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.