Question

So i have a statement:

 $r = mysql_query("Select type from boats where type like '%speed%'");

can I then apply the constructed resource to another query?

 $r2 = mysql_query("select * from assets where type in ".$r);

I am trying to do something similar to

 select * from assets where type in (select type from boats where type like '%speed%')

Answer 1

No, you can’t do this.

But you could combine the sql.

$sql = "Select type from boats where type like '%speed%'";
$r = mysql_query($sql);
$r2 = mysql_query("select * from assets where type in ($sql)");

Or instead of subquery, you could use a join.

$r2 = mysql_query("select a.* from assets a 
                   join boats b on a.type = b.type and b.type like '%speed%'");