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Home/ Questions/Q 6329507
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T17:40:50+00:00 2026-05-24T17:40:50+00:00

So I have a table that contains a column with a button. When this

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So I have a table that contains a column with a button. When this button is clicked, it toggles the class of the current table row and then replaces the button.

$(document).ready(function() {

    $(".checkOut").click(function() {
        var currentRow = $(this).closest("tr");
        $(currentRow).removeClass("checkedIn");
        $(currentRow).addClass("checkedOut");
        $(this).replaceWith('<button title="Check In" class="checkIn" value="true" name="check_in"><img alt="Check In" src="../images/check.png"></button>');
    } );

    $(".checkIn").click(function() {
        var currentRow = $(this).closest("tr");
        $(currentRow).removeClass("checkedOut");
        $(currentRow).addClass("checkedIn");
        $(this).replaceWith('<button title="Check Out" class="checkOut" value="true" name="check_out"><img alt="Check Out" src="../images/minus.png"></button>');
    } );

});

The initial click seems to work just fine. However when I click to change the state back to its orignal, it does not seem to work. I think it is a problem with replaceWith. Any help would be most appreciated!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T17:40:51+00:00Added an answer on May 24, 2026 at 5:40 pm
    $(document).ready(function() {
        $(".checkOut").live('click', function() {
            var $this = $(this),
                $currentRow = $this.closest("tr");
            $currentRow
                .removeClass("checkedIn")
                .addClass("checkedOut");
            $this.replaceWith('<button title="Check In" class="checkIn" value="true" name="check_in"><img alt="Check In" src="../images/check.png"></button>');
        });
    
        $(".checkIn").live('click', function() {
            var $this = $(this),
                $currentRow = $this.closest("tr");
            $currentRow
                .removeClass("checkedOut")
                .addClass("checkedIn");
            $this.replaceWith('<button title="Check Out" class="checkOut" value="true" name="check_out"><img alt="Check Out" src="../images/minus.png"></button>');
        });
    });
    

    1. You have to use .live() to attach a handler to the event for all elements which match the current selector, now and in the future.

    2. You were doing an unnecessary re-constructing of the variable currentRow. I added a $ sign, so you know it’s already a jQuery object, and not to re-construct it.

    In addition, I added code to cache the $currentRow and $this objects, so you won’t have to lookup the DOM every time you want to manipulate them.

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